7b^2-33b+3=0

Solution for 7b^2-33b+3=0 equation:

7b^2-33b+3=0

a = 7; b = -33; c = +3;
Δ = b2-4ac
Δ = -332-4·7·3
Δ = 1005
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-\sqrt{1005}}{2*7}=\frac{33-\sqrt{1005}}{14}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+\sqrt{1005}}{2*7}=\frac{33+\sqrt{1005}}{14}
$